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Direct/Inverse Variation

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Direct/Inverse Variation

Postby kevinnwhat » Thu 03.06.2008 8:09 pm

hello everyone, im sorry but i didnt really have any forum to put this one, so i thought i would give it a shot here. I cant get in touch with any of my friends so thats why im posting here.
Basically, i was absent when my teacher taught this lesson, and now i have a quiz on it, and i have no clue what im doing. Its on direct/indirect Variation. For the problem,

Y Varies Directly as X. If y = 14 when x = 2, find y when x = 5.

Is it set up as, k = y/x. K is your constant. So its k = 14/2 --> k = 7. Is this right? then you multiply it by 5? answer = 35?

when its inverse, is it the same thing but k = y * x (y times x)

im really confused, if anyone can help me with this i would really really really appreciate it.
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Re: Direct/Inverse Variation

Postby chikara » Thu 03.06.2008 8:32 pm

If it is direct variation y = kx so to find k you divide both sides by x, k = y/x as you have said.

y = 14, x = 2, k = ?
k = y/x = 14/2 = 7

Find y when x = 5
y = kx = 7 * 5 = 35

I agree with your solution :)

When it is inverse it is not "the same thing" but y = k/x so to find k multiply both sides by x, k = yx as you have said ;)
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Re: Direct/Inverse Variation

Postby kudamono-chan » Sun 03.16.2008 1:03 am

That was the one topic I really had trouble with on my Algebra 1 final...I ended up writing it on the one notecard we were allowed to have :oops:
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