hello everyone, im sorry but i didnt really have any forum to put this one, so i thought i would give it a shot here. I cant get in touch with any of my friends so thats why im posting here.
Basically, i was absent when my teacher taught this lesson, and now i have a quiz on it, and i have no clue what im doing. Its on direct/indirect Variation. For the problem,
Y Varies Directly as X. If y = 14 when x = 2, find y when x = 5.
Is it set up as, k = y/x. K is your constant. So its k = 14/2 > k = 7. Is this right? then you multiply it by 5? answer = 35?
when its inverse, is it the same thing but k = y * x (y times x)
im really confused, if anyone can help me with this i would really really really appreciate it.
Direct/Inverse Variation

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 chikara
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Re: Direct/Inverse Variation
If it is direct variation y = kx so to find k you divide both sides by x, k = y/x as you have said.
y = 14, x = 2, k = ?
k = y/x = 14/2 = 7
Find y when x = 5
y = kx = 7 * 5 = 35
I agree with your solution
When it is inverse it is not "the same thing" but y = k/x so to find k multiply both sides by x, k = yx as you have said
y = 14, x = 2, k = ?
k = y/x = 14/2 = 7
Find y when x = 5
y = kx = 7 * 5 = 35
I agree with your solution
When it is inverse it is not "the same thing" but y = k/x so to find k multiply both sides by x, k = yx as you have said
Don't complain to me that people kick you when you're down. It's your own fault for lying there

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Re: Direct/Inverse Variation
That was the one topic I really had trouble with on my Algebra 1 final...I ended up writing it on the one notecard we were allowed to have